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Simple print to stderr
By default the print statement sends to stdout
I want to send to stderr

Try

print "my meeage", file=sys.stderr

I got
> SyntaxError: invalid syntax

I try

print "my message", sys.stderr

But it still sent to stdout.
What is the syntax?

I wouldn't understand Python's manual




> print([object, ...][, sep=' '][, end='n'][, file=sys.stdout])ΒΆ
>
> Print object(s) to the stream file, separated by sep and followed by end. sep, end and file, if present, must be given as keyword arguments.
>
> All non-keyword arguments are converted to strings like str() does and written to the stream, separated by sep and followed by end. Both sep and end must be strings; they can also be None, which means to use the default values. If no object is given, print() will just write end.
>
> The file argument must be an object with a write(string) method; if it is not present or None, sys.stdout will be used.

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Re: Simple print to stderr [ In reply to ]
RC wrote:
> By default the print statement sends to stdout
> I want to send to stderr
>
> Try
>
> print "my meeage", file=sys.stderr
>
> I got
>> SyntaxError: invalid syntax
>
> I try
>
> print "my message", sys.stderr
>
> But it still sent to stdout.
> What is the syntax?
>
> I wouldn't understand Python's manual

<snip quote from the manual>

That's only in Python 3 (or 2.6 with the proper __future__ import).
Before that, print is a statement. You'd do it like this:

print >> sys.stderr, "whatever"

You should look at
<http://docs.python.org/reference/simple_stmts.html#the-print-statement>,
not Python 3's documentation.
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